[xquery-talk] Using axis in XQuery

[padmapriya ayyagari]

Hello,

The code given below provides an xslt solution for printing the path to a node.
However, I could not find how to use the axis (equivalent of 'select'
given below) in xquery.

I need a function such that : For every node returned as an answer to
an xquery which is a union of xqueries, I want the path from the root
to that node in the document.

<xsl:for-each select="ancestor-or-self::*">
  <xsl:text>/</xsl:text>
  <xsl:value-of select="name()" />
</xsl:for-each>

Also, between galax and saxon, which would you suggest for running
xqueries on xml documents?

Thank you so much Micahel and Jason for helping me out.

Padmapriya