[xquery-talk] Using axis in XQuery

padmapriya ayyagari asn.padmapriya at gmail.com
Tue Nov 30 22:05:34 PST 2004


The code given below provides an xslt solution for printing the path to a node.
However, I could not find how to use the axis (equivalent of 'select'
given below) in xquery.

I need a function such that : For every node returned as an answer to
an xquery which is a union of xqueries, I want the path from the root
to that node in the document.

<xsl:for-each select="ancestor-or-self::*">
  <xsl:value-of select="name()" />

Also, between galax and saxon, which would you suggest for running
xqueries on xml documents?

Thank you so much Micahel and Jason for helping me out.


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