[xquery-talk] Selecting Descendants

Brian Maso brian at blumenfeld-maso.com
Mon Jun 13 11:38:19 PDT 2005

Using ancestor:: axis (assuming processor supports it) makes it pretty easy:


Without using ancestor axis, I can't think of a way that wouldn't involve 
recursive descent:

declare function ns:descend($n as element) as element*
     for $e in $n/*[fn:node-name() != "B"] return ns:descend($e)

(: assume context node is an element...:)
if(fn:node-name() == "B")
   then .
   else ns:descend(.)

Brian Maso

At 08:13 AM 6/13/2005, EXTERNAL Kruse Peter (Praktikant; wrote:

>content-class: urn:content-classes:message
>Content-Type: multipart/alternative;
>         boundary="=_reb-r4665A816-t42ADA2EA"
>Hi folks
>I'm seeking a way to select only those descandants in a tree which fit a 
>criterion but not their descandants (even if those fit the critirion as well).
>I know, you can select with //node-name, but that will give back children 
>of node-name with name node-name as well and i don't want them (got it?)
>I have a tree like this
>         <B name="b1">
>                 <B name="b2">
>                 </B>
>         </B>
>         <B name="b3">
>         </B>
>         <B name="b4">
>         </B>
>         <A>
>                 <B name="b5">
>                         <B name="b6">
>                         </B>
>                 </B>
>         </A>
>And i want to select b1, b3, b4, b5 (but not b2 and b6, because their 
>parents (or one of there ancestors) is already selected).
>Any hints?
>Kind Regards
>   Peter
>talk at xquery.com
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