Correction: Re: [xquery-talk] XQuery function to do elementX/not-elementX chunking?

[David Sewell]

Someone will object that the sequence of sequences I claimed was my
goal will be flattened. What I really want as output is something like

<span>This text has <i>italics</i> and</span>
<span>an embedded ref</span>

so I'm really looking sequentially for node sequences defined as either
(1) a single <ref> or (2) a sequence of one or more non-<ref> nodes.

On Tue, 13 Sep 2005, David Sewell wrote:

> Given an XML element like this:
>
>   <ref>This text has <i>italics</i> and <ref>an embedded ref</ref> and
>     more text including <b>boldface</b> and <ref>another ref</ref>
>     and a bit more text.</ref>
>
> I want to break this into a sequence of sequences of its node children
> like so (with text nodes represented as strings, ignoring linebreaks):
>
> (
>   ( 'This text has ', <i>italics</i>, ' and ' ) ,
>   <ref>an embedded ref</ref>,
>   ( ' and more text including ', <b>boldface</b>, ' and ' ),
>   <ref>another ref</ref>,
>   'and a bit more text.'
> )
>
> In other words, pull out alternating sequences of (1) <ref> elements and
> (2) other nodes that are not <ref> elements. (The practical application is
> so that the <ref>s can be transformed into HTML <span>s without
> permitting embedded <spans>s -- they are HTML-legal but cause certain
> problems.)
>
> I was able to do this by writing a 10-line function that relies on a
> fairly clunky process of selecting all the <ref> children and then
> chunking the other nodes that precede and/or follow them; it relies on
> some fairly ugly use of preceding-sibling(), following-sibling(),
> name(), and the '>>' operator. It's so ugly that I don't want to inflict
> it this list (unless someone insists).
>
> Does anyone have a simple, elegant way to do this?
>
>

-- 
David Sewell, Editorial and Technical Manager
Electronic Imprint, The University of Virginia Press
PO Box 400318, Charlottesville, VA 22904-4318 USA
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Email: dsewell at virginia.edu   Tel: +1 434 924 9973
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