[xquery-talk] comparing consequtive elements

[Philippe Michiels]

Assuming that you meant sec 3 to contain:
<a attribute="3"/>
<a attribute="1"/>

Here's the expression ($x containing the fragment below)

for $s in $x/section
where
  $s/a[@attribute="3" and following-sibling::a[1]/@attribute="1"]
return data($s/@n)

Regards, 
Ph

> <eg>
>     <section n="1">
>         <a attribute="1"/>
>         <a attribute="2"/>
>     <section/>
>     <section n="2">
>         <a attribute="3"/>
>         <a attribute="1"/>
>     <section/>
>     <section n="3">
>         <a attribute="3"/>
>         <a attribute="3"/>
>     <section/>
>     <section n="4">
>         <a attribute="1"/>
>         <a attribute="1"/>
>     <section/>
> </eg>
> 
> say I'm looking for
> 
>  <a attribute="3"/>
>  <a attribute="1"/>
> 
> I need to look accross the <section> divisions too and return the 
> section number the transition starts in. so that snippet will produce 2 
> and 3.
> 
> any replies will be completely analysed! great thanks and no further 
> questions!
> 
> need a good book for XQuery/Xpath. any recommendations?
> 
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