[xquery-talk] node position

John Snelson jsnelson at sleepycat.com
Tue Jun 20 18:07:44 PDT 2006


You'll be wanting to use positional predicates:

$j/bookstore/book[1]
$j/bookstore/book[2]

John

fatma helmy wrote:
> let $j:=<bookstore>
> <book> ....</book>
> <book> ....</book>
> </bookstore>
> 
> how to distinguish between book nodes suppose i have
> no dtd and no node attribute identifier. can i get the
> node position to order them 1 , 2 ,, etc
> 
> 
> 
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-- 
John Snelson, Berkeley DB XML Engineer
Sleepycat Software, Inc
http://www.sleepycat.com

Contracted to Sleepycat through Parthenon Computing Ltd
http://blog.parthcomp.com/dbxml


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