[xquery-talk] XPath parser in Java
kfandre at gmail.com
Tue Oct 10 10:32:10 PDT 2006
There are few xpath javacc/jjtree grammars floating around that you can use
to generate your own parser. I used one a few years back to build an xpath
-> object-relational sql translater. If you dont find one, and your
interested, email mail me and I'll send you a grammar.
On 10/10/06, Frans Englich <frans.englich at telia.com> wrote:
> Real-To: Frans Englich <frans.englich at telia.com>
> On Tuesday 10 October 2006 11:45, Jonathan Robie wrote:
> > David Carlisle wrote:
> > >> Rather, I want the XPath parser to return an array or a
> > >> list or tree or anything where I can traverse step by step.
> > >
> > > There are xpath and xquery java parsers available from the working
> > > pages (maintained by Scott Boag, mainly)
> > > http://www.w3.org/2005/qt-applets/xqueryApplet.html
> > > This builds an in memory tree of the expression with methods to dump
> > > as indented text or as XML.
> > > I use it as the parser for xq2xml
> > > http://monet.nag.co.uk/xq2xml/index.html
> > These parsers are kept up to date with the latest drafts of XPath 2.0
> > and XQuery 1.0, and the text description in the specifications is
> > generated from the same grammar as the parser, all the examples in the
> > specifications (including the use cases) are tested with them, and they
> > have had wide review. So there are real advantages to using them. Unless
> > you need an XPath 1.0 parser.
> Even, the testing task force uses Scott's parser to check tests for parser
> errors, so its indirectly tested through the XQuery Test Suite.
> talk at x-query.com
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