[xquery-talk] calculated attribute/ namespace name

Andrew Welch andrew.j.welch at gmail.com
Wed Aug 15 15:43:05 PDT 2007

On 8/15/07, Uwe Küssner <uwekuessner at web.de> wrote:
> hello,
> a short question, i hope somebody can help.
> Let's say we have a XML documents like this:
> <ele xmlns:a="aa"  xmlns:b="bb"  name="foo" a:name="bar"
> b:name="foobar"  b:x="y" />
> The namespace names and attributes are not known before runtime, during
> runtime of a xquery script we have two variables of type string, for
> example:
> $namespace := "bb"
> $attribute :="name"
> here is the question: how can we extract the value of the attribute
> named $attribute with namespace name $namespace?
> In the example the value of  "b:name", i.e. "foobar".

How about:

@*[name() eq concat($namespace,':',$attribute)]/data(.)


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