[xquery-talk] calculated attribute/ namespace name
Andrew Welch
andrew.j.welch at gmail.com
Wed Aug 15 15:43:05 PDT 2007
On 8/15/07, Uwe Küssner <uwekuessner at web.de> wrote:
> hello,
>
> a short question, i hope somebody can help.
>
> Let's say we have a XML documents like this:
>
> <ele xmlns:a="aa" xmlns:b="bb" name="foo" a:name="bar"
> b:name="foobar" b:x="y" />
>
> The namespace names and attributes are not known before runtime, during
> runtime of a xquery script we have two variables of type string, for
> example:
> $namespace := "bb"
> $attribute :="name"
>
> here is the question: how can we extract the value of the attribute
> named $attribute with namespace name $namespace?
> In the example the value of "b:name", i.e. "foobar".
How about:
@*[name() eq concat($namespace,':',$attribute)]/data(.)
--
http://andrewjwelch.com
More information about the talk
mailing list