[xquery-talk] calculated attribute/ namespace name

John Snelson john.snelson at oracle.com
Wed Aug 15 15:41:51 PDT 2007


Something like this will work:

/ele/@*[node-name(.) = fn:QName($namespace, $attribute)]

John

Uwe Küssner wrote:
> hello,
> 
> a short question, i hope somebody can help.
> 
> Let's say we have a XML documents like this:
> 
> <ele xmlns:a="aa"  xmlns:b="bb"  name="foo" a:name="bar"  
> b:name="foobar"  b:x="y" />
> 
> The namespace names and attributes are not known before runtime, during 
> runtime of a xquery script we have two variables of type string, for 
> example:
> $namespace := "bb"
> $attribute :="name"
> 
> here is the question: how can we extract the value of the attribute 
> named $attribute with namespace name $namespace?
> In the example the value of  "b:name", i.e. "foobar".
> 
> thank you very much
> 
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