[xquery-talk] calculated attribute/ namespace name
John Snelson
john.snelson at oracle.com
Wed Aug 15 15:41:51 PDT 2007
Something like this will work:
/ele/@*[node-name(.) = fn:QName($namespace, $attribute)]
John
Uwe Küssner wrote:
> hello,
>
> a short question, i hope somebody can help.
>
> Let's say we have a XML documents like this:
>
> <ele xmlns:a="aa" xmlns:b="bb" name="foo" a:name="bar"
> b:name="foobar" b:x="y" />
>
> The namespace names and attributes are not known before runtime, during
> runtime of a xquery script we have two variables of type string, for
> example:
> $namespace := "bb"
> $attribute :="name"
>
> here is the question: how can we extract the value of the attribute
> named $attribute with namespace name $namespace?
> In the example the value of "b:name", i.e. "foobar".
>
> thank you very much
>
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