[xquery-talk] replacing a node in in-memory XML

Michael Kay mike at saxonica.com
Tue Nov 6 15:29:43 PST 2007

In the absence of XQuery updates (still a draft W3C spec) it's quite a bit
harder to do this in XQuery than in XSLT: you basically have to organize the
recursive walk down the tree copying nodes as you go yourself "by hand". If
you are comfortable with XSLT then this is definitely a task where XSLT
currently wins. It will get a lot easier with XQuery updates.
Michael Kay


From: talk-bounces at x-query.com [mailto:talk-bounces at x-query.com] On Behalf
Of Robert Walpole
Sent: 06 November 2007 15:05
To: talk at xquery.com
Subject: [xquery-talk] replacing a node in in-memory XML


I am trying to figure out the best way to replace a node within an in-memory
XML fragment. 

For example, lets say I have the following fragment in memory. 

                        <service value="true">2</service> 

.and want to replace the services node with the following. 

        <service value="false">1</service> 
        <service value="true">2</service> 
        <service value="false">3</service> 

Is there a way of doing this in XQuery? 

Obviously I could use an XSL transformation, which would give me the result
I want, but maybe there is a more efficient way using XQuery?

Rob Walpole 
Devon Portal Developer 
Email robert.walpole at devon.gov.uk 
Web  <http://www.devonline.gov.uk> http://www.devonline.gov.uk 

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