[xquery-talk] XPath/XQuery equivalent of xsl:number?

[Adam Retter]

Joe,

In eXist-db (which I happen to know you are using), if you want the
format-number function, you can just call - xsl:format-number(...)
from XQuery, see the signature for in the eXist-db function guide -
xsl:format-number($number as numeric?, $format as xs:string) xs:string

However I doubt format-number function is actually what you want as it
doesnt appear to support roman numerals. As such I think Ken's example
is a good start

On 17 November 2011 19:04, Joe Wicentowski <joewiz at gmail.com> wrote:
> Hi all,
>
> I am constructing a table of contents based on a TEI document (whose
> structure consists primarily of nested divs), and would like to be
> able to generate appropriate heading levels for each the table of
> contents hierarchy.  Specifically, I want to be able to generate the
> "I", "II", "A", "B", and "a" bits in:
>
> I. Chapter 1
> II. Chapter 2
>  A. Section 1
>  B. Section 2
>    a) Subsection 1
>
> Put another way, borrowing from CSS terminology, I need to be able to
> format an integer as "upper-roman", "upper-alpha", and "lower-alpha."
>
> Borrowing from XSL terminology, I need to perform the equivalent
> function of <xsl:number>, as in:
>
>  <xsl:number value="2" format="I'/> ==> returns "II"
>  <xsl:number value="2" format="a'/> ==> returns "b"
>  <xsl:number value="2" format="A'/> ==> returns "B"
>
> I think what I really need is XPath 3.0's fn:format-integer()
> function[1], but it appears that XPath 3.0 is still at the Working
> Draft stage.
>
> So my question: Of course I could hack my own format-integer()
> function together (indeed, my current kludge is to pipe out my
> integers to an XSL stylesheet), but is there an XPath or XQuery
> library that would let me do this?
>
> Thanks,
> Joe
>
> [1] http://www.w3.org/TR/xpath-functions-30/#func-format-integer
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Adam Retter

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