[xquery-talk] Fuctions and variables in replacement string of fn:replace()
geert.josten at dayon.nl
Wed May 1 01:32:38 PDT 2013
Or switch to xsl:analyze-string..
> -----Oorspronkelijk bericht-----
> Van: talk-bounces at x-query.com [mailto:talk-bounces at x-query.com]
> Namens Michael Kay
> Verzonden: woensdag 1 mei 2013 10:02
> Aan: liam at w3.org
> CC: XQuery Talk; David Sewell
> Onderwerp: Re: [xquery-talk] Fuctions and variables in replacement
> of fn:replace()
> On 1 May 2013, at 04:14, Liam R E Quin wrote:
> > On Tue, 2013-04-30 at 23:01 -0400, David Sewell wrote:
> >> When using fn:replace(), is it kosher or illegal to construct the
> >> replacement string dynamically using a function?
> Yes. XQuery is an orthogonal language, any expression can be replaced by
> different expression that returns the same value.
> >> In some cases this
> >> seems to work (tested in Saxon and MarkLogic):
> >> xquery version "1.0";
> >> let $string := "Now, let's SEND OUT for QUICHE!!"
> >> let $match := "[A-Z][A-Z]+"
> >> return replace($string, $match, concat("$0","$0"))
> >> ==> Now, let's SENDSEND OUTOUT for QUICHEQUICHE!!
> >> but in other cases it doesn't. For example, lower-case("$0") has no
> >> effect.
> It should have no effect. It's the same as replace($string, $match,
> which replaces every string that matches $match with itself.
> >> And substring("$0", 1, 1) throws an error.
> Because '$' is not a valid replacement string.
> OK, I think I've understood what you wanted (maybe!). You didn't want to
> construct the replacement string using a function, you wanted to apply a
> function to the matching substrings found by the matching operation: you
> want a higher-order replace(). Saxon has such a thing in the form of
> saxon:analyze-string (see
> string) but in 3.0 the WG took a different direction in its definition
> fn:analyze-string(), which is probably easier for ordinary mortals to
> with: http://www.w3.org/TR/xpath-functions-30/#func-analyze-string
> Michael Kay
> talk at x-query.com
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