[xquery-talk] Collections - family relationships
andrew.j.welch at gmail.com
Sun Jan 5 14:09:13 PST 2014
On 5 January 2014 21:20, Michael Kay <mike at saxonica.com> wrote:
> On 5 Jan 2014, at 20:59, David Lee <dlee at calldei.com> wrote:
>> Given those truths ...
>> If you do have a sequence from fn:collection() or another function you *can* find the position of a document in that collection and its 'sibling'
>> Note: this may be a horribly inefficient thing to do so buyer beware ....
>> let $c := fn:collection(),
>> $doc := local:pick-a-random-doc( $c ),
>> $prev := $c[ fn:index-of( $c , $doc ) - 1 ] (: Might be bad to do on the first or only document :)
>> return $c
> This only works if all the documents have distinct string-values.
> A more efficient and reliable approach would be
> min(for $c at $i in collection() where $c is $doc return $i)
Couldn't you use uri-collection() to give you an order, rather than
the collection() directly?
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