[xquery-talk] What does [.] do.

[Ihe Onwuka]

I don't have a preferred order of precedence and no they shouldn't
both be there.

So [1] is really saying get me the first string that is not the empty
string or the first non-empty node?

On Mon, Jan 27, 2014 at 3:14 PM, David Lee <dlee at calldei.com> wrote:
> I wouldnt do
>
> (readingMaterial|publication)/string()
> or
> (xs:string(readingMaterial),xs:string(publication))[.]
>
> unless you absolutely knew for sure that only 1 existed.
> If both exist you will get 2 strings.
>
> In the first place you get them in document order,
> in the second case in the order specified.
>
> I would do
>
>    (xs:string(readingMaterial),xs:string(publication))[1]
> or just
>     (readingMaterial,publication)[1]/string()
>
>
> which gives me readingMaterial if it exists, and if it doesnt exist then publication.
> but never both and always in the order of precidence I asked
>
> .
> On 27/01/2014 14:55, Ihe Onwuka wrote:
>> I am using one transformation for two different data sources with two
>> different schemas.
>>
>> One site may call a resoure readingMaterial another site may call the
>> same concept a publication, but they are otherwise similar and you may
>> want to treat them as such.
>>
>> (xs:string(readingMaterial),xs:string(publication))[.]
>>
>
>
>
> I'd probably write that as
>
> (readingMaterial|publication)/string()
>
> or if you know that exactly one of them is always there
>
>
>
> string(readingMaterial|publication)
>
>
> David
>
>
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