[xquery-talk] Xquery : Sort and get only the first record
sudheshna iyer
sudheshnaiyer at yahoo.com
Sun Nov 1 11:51:18 PST 2015
Team,
I have an xml which has multiple jobs elements. I want to sort the jobs and want to output only the latest job. Note that <EndDate> can be empty indicating that it is the current job.
Basically I want to order by jobs/job/EndDate in descending fashion and select only the first record..
How do I do that using xquery?
Input request: <?xml version="1.0" encoding="UTF-8"?><Request> <SessionInfo> <uid>qq</uid> <pwd>qq</pwd> </SessionInfo> <Param> <CustomerInfo> <Contact> <Number>123</Number> <Name>aaa bbb</Name> <Jobs> <job> <Name>Analyst</Name> <Id>1</Id> <StartDate>01-01-2015</StartDate> <EndDate>08-30-2015</EndDate> </job> <job> <Name>Programmer</Name> <Id>2</Id> <StartDate>08-31-2015</StartDate> <EndDate /> </job> </Jobs> </Contact> </CustomerInfo> </Param></Request>
Expected output:
<?xml version="1.0" encoding="UTF-8"?><Request> <SessionInfo> <uid>qq</uid> <pwd>qq</pwd> </SessionInfo> <Param> <CustomerInfo> <Contact> <Number>123</Number> <Name>aaa bbb</Name> <Jobs> <job> <Name>Programmer</Name> <Id>2</Id> <StartDate>08-31-2015</StartDate> <EndDate/> </job> </Jobs> </Contact> </CustomerInfo> </Param></Request>
Your help is greatly appreciated.
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