[xquery-talk] Function for determining one XPath as subset of another
Pavel Velikhov
pavel.velikhov at gmail.com
Fri Jan 29 14:29:16 PST 2016
Trees won’t help much here. The difficulty with path expression is due to the // step, which adds non-determinism.
//w/x subsumes /w/x/y/z/w/x
//w/w doesn’t subsume /w/x/w
Regular languages also have determinism and all the algorithms for them are exceptionally well-studied.
Or you can do an algorithm with backtracking, but it could get hairy.
> On 29 Jan 2016, at 20:53, W.S. Hager <wshager at gmail.com> wrote:
>
> This is the best I (actually Google) can do.
>
> Proof:
> https://coq.inria.fr/library/Coq.MSets.MSetGenTree.html <https://coq.inria.fr/library/Coq.MSets.MSetGenTree.html>
> Test:
>
> http://www.geeksforgeeks.org/check-if-a-binary-tree-is-subtree-of-another-binary-tree/ <http://www.geeksforgeeks.org/check-if-a-binary-tree-is-subtree-of-another-binary-tree/>
> At some point I'll look into this myself, it's a nice challenge.
>
>
> donderdag 28 januari 2016 heeft Pavel Velikhov <pavel.velikhov at gmail.com <>> het volgende geschreven:
> Hmm.. testing subsumption is not as trivial as I thought. Here's a cleaner way to do it: represent both path expressions as DFAs and then test subsumption. You'll get DFAs A and B and then test if minimized(B-A) is empty.
>
>
> --
> W.S. Hager
> Lagua Web Solutions
> http://lagua.nl <http://lagua.nl/>
>
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