From rpbourret at rpbourret.com  Thu Nov  9 10:40:23 2017
From: rpbourret at rpbourret.com (Ronald Bourret)
Date: Thu, 9 Nov 2017 10:40:23 -0800
Subject: [xquery-talk] Return nodes and text between nodes
In-Reply-To: <012501d35988$690e1030$3b2a3090$@envisn.com>
References: <012501d35988$690e1030$3b2a3090$@envisn.com>
Message-ID: <5cd79dc0-724e-5670-66ba-da898cdf13a5@rpbourret.com>

 From the XPath specification:

- child::* selects all element children of the context node

- child::text() selects all text node children of the context node

- child::node() selects all the children of the context node, whatever 
their node type

Since "child" is the default axis, you can omit it. Thus, $expr/* will 
only return element children, as you have seen. If you want all 
children, use $expr/node(). If you only want text children, use 
$expr/text().

-- Ron

On 11/9/2017 10:27 AM, Gary Larsen wrote:
> Hi,
> 
> Trying to process both node and text children in a for loop.? For some 
> reason this escapes me.
> 
> let $expr := 
> <expression><refobj>REFOBJ1</refobj>TEXT1<refobj>REFOBJ2</refobj></expression>
> 
> for $x in $expr/* return $x
> 
> This returns:
> 
> <refobj>REFOBJ1</refobj>
> <refobj>REFOBJ2</refobj>
> 
> How do I access TEXT1 in a loop?
> 
> Thanks,
> 
> Gary
> 
> 
> 
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