[xquery-talk] calculated attribute/ namespace name

[Uwe Küssner]

Hi John

thank you. I changed your solution to

$ele/@*[node-name(.) = fn:QName($namespace,  concat("arbitrary:",  
$attribute))  ]

than it seems to works as well.

uwe



John Snelson schrieb:
> Something like this will work:
>
> /ele/@*[node-name(.) = fn:QName($namespace, $attribute)]
>
> John
>
> Uwe Küssner wrote:
>> hello,
>>
>> a short question, i hope somebody can help.
>>
>> Let's say we have a XML documents like this:
>>
>> <ele xmlns:a="aa"  xmlns:b="bb"  name="foo" a:name="bar"  
>> b:name="foobar"  b:x="y" />
>>
>> The namespace names and attributes are not known before runtime, 
>> during runtime of a xquery script we have two variables of type 
>> string, for example:
>> $namespace := "bb"
>> $attribute :="name"
>>
>> here is the question: how can we extract the value of the attribute 
>> named $attribute with namespace name $namespace?
>> In the example the value of  "b:name", i.e. "foobar".
>>
>> thank you very much
>>
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