[xquery-talk] where clause

[Michael Sokolov]

I see - nice!  Still trying to wrap my head around it to generalize, but 
I see your point.

-Mike

On 03/28/2013 02:22 PM, daniela florescu wrote:
> Not in the general case of such pattern -- because of cardinality.
> (I told you XQuery is twisted :-)
>
> Imagine that the function would have looked like this instead of the one I wrote:
>
>
> declare function foo($x)
> {
>     if ($x/@a) then ($x, $x) else<b/>
> };
>
> then count(...) of the total result  is different  !
>
> :-)
>
> Dana
>
>
>
>    
>>>
>>>        
>> Yes, that is twisted for sure.  But isn't it also equivalent to:
>>
>> for $x in Blah1
>> for $y in Blah2
>> for $z in foo($y)[. is .]
>> return $x
>>
>> ?
>>
>> not that that really makes any difference, in some sense, but given the problem as stated, I don't think a where clause is required
>>
>> -- 
>> Michael Sokolov
>> Senior Architect
>> Safari Books Online
>>
>> _______________________________________________
>> talk at x-query.com
>> http://x-query.com/mailman/listinfo/talk
>>      
>    


-- 
Michael Sokolov
Senior Architect
Safari Books Online